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--- 183_notes:curving_motion [2014/09/24 17:23] – [A change in direction] caballero
+++ 183_notes:curving_motion [2014/09/24 17:43] – [A change in direction] caballero
@@ Line 58: / Line 58: @@
 $$\dfrac{d \hat{p}}{d t} = \dfrac{|\vec{v}|}{R} \hat{n}$$
+[{{183_notes:mi3e_05-026.jpg?250|The perpendicular component of the net force points inward towards the turn.}}]
 where the unit vector, $\hat{n}$, always points inward towards the turn. For more general trajectories, the value of $R$ is the radius of curvature of the arc, that is, it is the radius of the circle that has exactly the same curvature at the location of interest.
@@ Line 65: / Line 67: @@
 $$\vec{F}_{net,\perp} = |\vec{p}|\dfrac{d \hat{p}}{d t} = \dfrac{|\vec{p}||\vec{v}|}{R} \hat{n} =\dfrac{mv^2}{R} \hat{n} $$
+==== Relationship to the tangential and centripetal accelerations ====
+In your previous studies, you might come acres the [[http://en.wikipedia.org/wiki/Acceleration#Tangential_and_centripetal_acceleration|tangential acceleration and the centripetal acceleration]]. This are directly connected to the definitions of the parallel and perpendicular components of the net force. You can write the net force as the sum of these parallel and perpendicular components.
+$$\vec{F}_{net} = \vec{F}_{\parallel} + \vec{F}_{\perp}$$