183_notes:examples:a_meter_stick_on_the_ice

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183_notes:examples:a_meter_stick_on_the_ice [2014/11/16 21:20] – created pwirving183_notes:examples:a_meter_stick_on_the_ice [2014/11/20 16:00] pwirving
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 === Facts === === Facts ===
  
 +Mass of meter stick 300g
  
 +Pull at end of meter stick at right angles to the stick: 6N
  
 +Remember a meter stick is a meter long
  
  
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 === Lacking === === Lacking ===
  
 +Rate of change of the center-of-mass speed $v_{CM}$?
  
 +Rate of change of the angular speed $\omega$?
  
  
 === Approximations & Assumptions === === Approximations & Assumptions ===
  
 +No friction due to ice
  
  
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 === Representations === === Representations ===
  
 +System: Stick
  
-{{course_planning:projects:mi3e_11-006.jpg?400}}+SurroundingsYour hand (pulling); ice (negligible effect)
  
 +{{183_projects:mi3e_11-050.jpg?300}}
  
 +$\frac{d\vec{P}}{dt}$ = $\vec{F}_{net}$
  
 +$\frac{d\vec{L}_{rot}}{dt}$ = $\vec{\tau}_{net,CM}$
  
-=== Solution ===+$\tau r_{A}Fsin \theta$
  
-Direction: At both locations, the direction of the translational angular momentum of the comet is in the -z direction (into the computer); determined by using the right-hand rule. 
  
-At location 1: 
  
-$\mid\vec{L}_{trans,Sun}\mid$ = $(8.77$ x $10^{10}m)(2.2$ x $10^{14}kg)(5.46$ x $10^4m/s)sin 90^{\circ}$ 
  
-$1.1x $10^{30}$ $kg \cdot m^2/s$+=== Solution === 
 + 
 +From the momentum principle: 
 + 
 +$d\vec{P}/dt = d(m\vec{v}_{CM})/dt = \vec{F}_{net}$ 
 + 
 +$dv_{CM}/dt = (6N)/(0.3kg) = 20m/s^2$
  
-$\vec{L}_{trans,Sun}$ = $\langle{0, 0, -1.1 x 10^30}\rangle$ $kg \cdot m^2/s$+Angular Momentum Principle about center of mass:
  
 +$d\vec{L}_{rot}/dt = \vec{\tau}_{net,CM}$
  
-At location 2:+Component into screen (-z direction):
  
-$\mid\vec{L}_{trans,Sun}\mid$ $(1.19$ x $10^{12}m)(2.2$ x $10^{14}kg)(1.32$ x $10^4m/s)sin 17.81^{\circ}$+$Id\omega/dt = (0.5m)(6N)sin90^{\circ} = 3N \cdot m$
  
-$= 1.1$ x $10^{30}$ $kg \cdot m^2/s$+$d\omega/dt (3N \cdot m)/[(0.kg \cdot m^2)/12] = 120 radians/s^2$
  
-$\vec{L}_{trans,Sun}$ = $\langle{00, -1.1 x 10^30}\rangle$ $kg \cdot m^2/s$+In vector terms, $d\vec{\omega}/dtpoints into the pagecorresponding to the fact that the angular velocity points into the page and is increasing.
  • 183_notes/examples/a_meter_stick_on_the_ice.txt
  • Last modified: 2014/11/20 16:28
  • by pwirving