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183_notes:examples:calculating_the_force_due_to_a_stretched_spring [2014/07/22 02:42] – caballero | 183_notes:examples:calculating_the_force_due_to_a_stretched_spring [2014/07/22 04:54] – pwirving | ||
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$ |\vec{s}| = |L - L_0|$ | $ |\vec{s}| = |L - L_0|$ | ||
- | {{183_notes: | + | {{183_notes: |
+ | |||
+ | {{183_notes: | ||
<WRAP todo> | <WRAP todo> | ||
==== Solution ==== | ==== Solution ==== | ||
- | |||
- | <WRAP todo> | ||
To determine the spring force, you will need to compute: | To determine the spring force, you will need to compute: | ||
Line 42: | Line 42: | ||
These can be used to compute the unit (direction) vector for the stretch ($\hat{s}$), | These can be used to compute the unit (direction) vector for the stretch ($\hat{s}$), | ||
- | | + | |
- | You can then compute the magnitude of the stretch (|\vec{s}|): | + | You can then compute the magnitude of the stretch |
$$ |\vec{s}| = |L - L_0| = 0.38m - 0.20m = 0.18m$$ | $$ |\vec{s}| = |L - L_0| = 0.38m - 0.20m = 0.18m$$ | ||
Finally, you can compute the force: | Finally, you can compute the force: | ||
- | $$\vec{F} = -k_s|\vec{s}|\hat{s} = -(8N/ | + | $$\vec{F} = -k_s|\vec{s}|\hat{s} = -(8N/ |
+ | which points to the left. That is consistent with the diagram above. | ||