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--- 183_notes:examples:momentumfast [2014/07/10 14:18] – [Solution] caballero
+++ 183_notes:examples:momentumfast [2014/07/10 14:21] – [Solution] caballero
@@ Line 38: / Line 38: @@
 Finally, we compute the momentum vector.
+$$\vec{p} = \gamma m \vec{v} = (1.02) (9.11\times10^{-31} kg) \langle -2.05\times10^7, 6.02\times10^7, 0\rangle\dfrac{m}{s} = \langle -1.91 \times 10^{-23}, 5.61\times10^{-23},0\rangle\:\dfrac{kg\:m}{s}$$