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Both sides previous revision Previous revision Next revision | Previous revision Next revisionBoth sides next revision | ||
183_notes:examples:sliding_to_a_stop [2014/09/22 04:24] – pwirving | 183_notes:examples:sliding_to_a_stop [2014/09/22 04:30] – pwirving | ||
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$ F_N = mg \, | $ F_N = mg \, | ||
- | Combining these two equations and substituting in mg for F_N and writing $ p_x = mv_x $, we get the following equation: | + | Combining these two equations and substituting in mg for $F_N$ and writing $ p_x = \Delta(mv_x) $, we get the following equation: |
$ \Delta(mv_x) = -mg\Delta t $ | $ \Delta(mv_x) = -mg\Delta t $ | ||
- | $ \Delta(v_x) = - g\Delta t $ | + | Cancel the masses |
+ | |||
+ | $ \Delta(v_x) = - g\Delta t $ | ||
+ | |||
+ | Rearrange to solve for $\Delta t$ and sub in 0 - $v_{xi}$ for $ \Delta(v_x)$ | ||
$ \Delta(t) = \dfrac{0 - v_{xi}}{-g} = \dfrac{v_{xi}}{g} $ | $ \Delta(t) = \dfrac{0 - v_{xi}}{-g} = \dfrac{v_{xi}}{g} $ | ||
+ | |||
+ | Fill in values for variables and solve for $\Delta t$ | ||
$ \Delta(t) = \dfrac{6 m/s}{0.4 (9.8 N/kg)} = 1.53s $ | $ \Delta(t) = \dfrac{6 m/s}{0.4 (9.8 N/kg)} = 1.53s $ |