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183_notes:model_of_a_wire [2015/09/19 11:17] – [Modeling the interatomic bond as spring] caballero | 183_notes:model_of_a_wire [2015/09/19 11:25] – [Modeling the solid wire] caballero | ||
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$$s = \dfrac{mg}{k} = \dfrac{100N}{100N/ | $$s = \dfrac{mg}{k} = \dfrac{100N}{100N/ | ||
- | When we attach a second 100N/m spring to the end of the first and then attach the mass, the springs | + | Hence, a single 100 N/m spring will stretch precisely 1m when a 100N ball is hung from it. |
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+ | When we attach a second 100N/m spring to the end of the first and then attach the mass, both springs | ||
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+ | //In series, each spring stretches as if the mass were attached to just that spring//, and the sum of all those stretches gives the overall stretch. | ||
== Modeling two end-to-end springs as one spring (effective spring constant) == | == Modeling two end-to-end springs as one spring (effective spring constant) == | ||
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$$s = \dfrac{mg}{2k} = \dfrac{100N}{200N/ | $$s = \dfrac{mg}{2k} = \dfrac{100N}{200N/ | ||
- | When we attach a second 100N/m spring to the ball, the springs both stretch 0.5m. That is, the overall stretch of the spring-mass system is half of what it is with one spring. //In parallel, each spring stretches the same amount//. | + | When we attach a second 100N/m spring to the ball, the springs both stretch 0.5m. That is, the overall stretch of the spring-mass system is half of what it is with one spring. |
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+ | //In parallel, each spring stretches the same amount//. | ||
== Modeling two side-by-side springs as one spring (effective spring constant) == | == Modeling two side-by-side springs as one spring (effective spring constant) == |