183_notes:model_of_a_wire

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183_notes:model_of_a_wire [2015/09/19 11:20] – [Modeling the solid wire] caballero183_notes:model_of_a_wire [2015/09/19 11:25] – [Modeling the solid wire] caballero
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 Hence, a single 100 N/m spring will stretch precisely 1m when a 100N ball is hung from it. Hence, a single 100 N/m spring will stretch precisely 1m when a 100N ball is hung from it.
  
-When we attach a second 100N/m spring to the end of the first and then attach the mass, both springs will stretch 1m. That is, the overall stretch of the spring-mass system is 2m. //In series, each spring stretches as if the mass were attached to just that spring//, and the sum of all those stretches gives the overall stretch.+When we attach a second 100N/m spring to the end of the first and then attach the mass, both springs will stretch 1m. That is, the overall stretch of the spring-mass system is 2m.  
 + 
 +//In series, each spring stretches as if the mass were attached to just that spring//, and the sum of all those stretches gives the overall stretch.
  
 == Modeling two end-to-end springs as one spring (effective spring constant) == == Modeling two end-to-end springs as one spring (effective spring constant) ==
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 $$s = \dfrac{mg}{2k} = \dfrac{100N}{200N/m} = 0.5m$$ $$s = \dfrac{mg}{2k} = \dfrac{100N}{200N/m} = 0.5m$$
  
-When we attach a second 100N/m spring to the ball, the springs both stretch 0.5m. That is, the overall stretch of the spring-mass system is half of what it is with one spring. //In parallel, each spring stretches the same amount//.+When we attach a second 100N/m spring to the ball, the springs both stretch 0.5m. That is, the overall stretch of the spring-mass system is half of what it is with one spring.  
 + 
 +//In parallel, each spring stretches the same amount//.
  
 == Modeling two side-by-side springs as one spring (effective spring constant) == == Modeling two side-by-side springs as one spring (effective spring constant) ==
  • 183_notes/model_of_a_wire.txt
  • Last modified: 2021/03/13 19:40
  • by stumptyl