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| Both sides previous revision Previous revision | Next revisionBoth sides next revision | ||
| 184_notes:examples:week14_ac_graph [2017/11/28 16:50] – [Solution] tallpaul | 184_notes:examples:week14_ac_graph [2017/11/28 16:50] – [Solution] tallpaul | ||
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| $$f = \frac{1}{\tau} = \frac{1}{0.04\text{ s}} = 25\text{ Hz}$$ | $$f = \frac{1}{\tau} = \frac{1}{0.04\text{ s}} = 25\text{ Hz}$$ | ||
| - | We are also now equipped to write a equation for the alternating current. We will use a sine function rather than a cosine function, since the current begins at $I=0$, and increasing. The amplitude will provide the factor out front: | + | We are also now equipped to write a equation for the alternating current. We will use a sine function rather than a cosine function, since the current begins at $I=0$, and increases. The amplitude will provide the factor out front: |
| $$I=I_0\sin(2\pi \cdot f \cdot t) = (0.3\text{ A}) \cdot \sin(2\pi \cdot 25\text{ Hz} \cdot t)$$ | $$I=I_0\sin(2\pi \cdot f \cdot t) = (0.3\text{ A}) \cdot \sin(2\pi \cdot 25\text{ Hz} \cdot t)$$ | ||