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184_notes:examples:week14_b_field_capacitor [2017/11/27 03:12] – tallpaul | 184_notes:examples:week14_b_field_capacitor [2017/11/28 02:12] – dmcpadden | ||
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===== Magnetic Field from a Charging Capacitor ===== | ===== Magnetic Field from a Charging Capacitor ===== | ||
- | Suppose you have a parallel plate capacitor that is charging with a current $I=3 \text{ A}$. The plates are circular, with radius $R=10 \text{ m}$ and a distance $d=1 \text{ cm}$. What is the magnetic field in the plane parallel to but in between the plates? | + | Suppose you have a parallel plate capacitor that is charging with a current $I=3 \text{ A}$. The plates are circular, with radius $R=10 \text{ m}$ and a distance $d=1 \text{ cm}$ apart. What is the magnetic field in the plane parallel to but in between the plates? |
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===Approximations & Assumptions=== | ===Approximations & Assumptions=== | ||
* We are only concerned about a snapshot in time, so the current is $I$, even though this may change at a later time as the capacitor charges. | * We are only concerned about a snapshot in time, so the current is $I$, even though this may change at a later time as the capacitor charges. | ||
- | * The electric field between the plates is the same as the electric field between infinite plates. | + | * The electric field between the plates is the same as the electric field between infinite plates |
* The electric field outside the plates is zero. | * The electric field outside the plates is zero. | ||
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====Solution==== | ====Solution==== | ||
- | We wish to find the magnetic field in the plane we've shown in the representations. Due to the circular symmetry of the problem, we choose a circular loop in which to situate our integral $\int \vec{B}\bullet\text{d}\vec{l}$. We also choose for the loop to be the perimeter of a flat surface, so that the entire thing lies in the plane of interest, and there is no enclosed current (so $I_{enc} = 0$). We show the drawn loop below, split into two cases on the radius of the loop. | + | We wish to find the magnetic field in the plane we've shown in the representations. |
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+ | Due to the circular symmetry of the problem, we choose a circular loop in which to situate our integral $\int \vec{B}\bullet\text{d}\vec{l}$. We also choose for the loop to be the perimeter of a flat surface, so that the entire thing lies in the plane of interest, and there is no enclosed current (so $I_{enc} = 0$ - there is only the changing electric field). We show the drawn loop below, split into two cases on the radius of the loop. | ||
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- | Below, we also draw the direction of the magnetic field along the loops. We know the magnetic field is directed along our circular loop -- if it pointed in or out a little bit, we may be able to conceive of the closed surface with magnetic flux through it, which would imply the existence of a magnetic monopole. This cannot be the case! We also know that the field is directed counterclockwise, | + | Below, we also draw the direction of the magnetic field along the loops. We know the magnetic field is directed along our circular loop (since the changing electric flux creates a curly magnetic field) |
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