184_notes:examples:week2_electric_potential_positive_point

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184_notes:examples:week2_electric_potential_positive_point [2017/08/28 21:17] – [Example: Electric Potential from a Positive Point Charge] tallpaul184_notes:examples:week2_electric_potential_positive_point [2018/02/03 21:15] tallpaul
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-===== Example: Electric Potential from a Positive Point Charge ===== +===== Example: Electric Potential from a Positively Charged Balloon ===== 
-FIXME Could we maybe add some numbers here? Like R=0.1 cm and Q=5*10^-7 C? Could do this as a charged balloon or something. +Suppose we have a positively charged balloon with total charge $Q=5.0\cdot 10^{-9} \text{ C}$. What is the electric potential (also called voltage) at a point $P$, which is a distance $R=50 \text{ cm}$ from the center of the balloon?
- +
-Suppose we have a positively charged balloon with total charge $Q=5\cdot 10^{-7} \text{ C}$. What is the electric potential at a point $P$, which is a distance $R=50 \text{ cm}$ from the center of mass of the balloon? A diagram below shows a rough sketch. +
-{{ 184_notes:2_potential_positive_balloon.png?150 |Charged Balloon, and Point P}}+
  
 ===Facts=== ===Facts===
-  * The balloon has total charge $Q=5\cdot 10^{-7} \text{ C}$. +  * The balloon has total charge $Q=5.0\cdot 10^{-9} \text{ C}$. 
-  * The point $P$ is a distance $R=50 \text{ cm}$ away from the center of mass of the balloon.+  * The point $P$ is a distance $R=50 \text{ cm}$ away from the center of the balloon
 +  * The electric potential due to a point charge can be written as $$V = \frac{1}{4\pi\epsilon_0}\frac{q}{r},$$ where $q$ represents the charge and $r$ is the distance.
  
-===Lacking=== +===Representations=== 
-  * The electric potential at $P$.+<WRAP TIP> 
 +=== Assumption === 
 +We assume $P$ lies outside of the balloonWe make this assumption because it was not specified, but this seems to make more sense than $P$ being inside the balloon. This also helps us draw the representation below, which can be used to bolster our approximation later on of the balloon as a point charge. 
 +</WRAP>
  
-===Approximations & Assumptions=== +{{ 184_notes:2_potential_positive_balloon.png?150 |Charged Balloon, and Point P}}
-  * The electric potential at $P$ is due entirely to the balloon. +
-  * $P$ lies outside of the balloon. +
-  * The balloon's electric field outside the balloon acts like a point charge centered at the center of mass of the balloon. +
-  * The electric potential infinitely far away from the balloon is $0 \text{ V}$.+
  
-===Representations=== +===Goal=== 
-  * The electric potential due to a point charge (to which we are approximating the balloon) can be written as $$V = \frac{1}{4\pi\epsilon_0}\frac{q}{r},$$ where $q$ represents our charge and $ris our distance.+  * Find the electric potential at $P$.
  
 ====Solution==== ====Solution====
 +<WRAP TIP>
 +=== Approximation ===
 +We approximate the balloon as a point charge. We do this because we have the tools to find the electric potential from a point charge. This seems like a reasonable approximation because the balloon is not too spread out, and we are interested in points outside the balloon. so the balloon might "look" like a point charge from the perspective of an observation location that is little far away.
 +</WRAP>
 +
 +<WRAP TIP>
 +=== Assumption ===
 +The electric potential infinitely far away from the balloon is $0 \text{ V}$. Read [[184_notes:superposition#Superposition_of_Electric_Potential|here]] for why this is important.
 +</WRAP>
 +
 The electric potential at $P$ is given by The electric potential at $P$ is given by
 \begin{align*} \begin{align*}
 V &= \frac{1}{4\pi\epsilon_0}\frac{q}{r} \\ V &= \frac{1}{4\pi\epsilon_0}\frac{q}{r} \\
-  &= \frac{1}{4\pi\epsilon_0}\frac{Q}{R} \\+  &= \frac{1}{4\pi\cdot 8.85\cdot 10^{-12} \frac{\text{C}}{\text{Vm}}}\frac{5\cdot 10^{-9} \text{ C}}{0.5 \text{ m}} \\ 
 +  &= 90 \text{ V}
 \end{align*} \end{align*}
  • 184_notes/examples/week2_electric_potential_positive_point.txt
  • Last modified: 2018/05/17 16:48
  • by curdemma