184_notes:examples:week2_moleoelectrons

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184_notes:examples:week2_moleoelectrons [2017/08/24 17:29] dmcpadden184_notes:examples:week2_moleoelectrons [2018/05/17 15:16] curdemma
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- +[184_notes:charge|Return to Electric Charge Page] 
-===== Example: How much total charge is in one mole of electrons=====+===== Example: Find the total charge for a mole of electrons =====
 How much total charge (in coulombs) is in one mole of electrons? How much total charge (in coulombs) is in one mole of electrons?
  
 ===Facts=== ===Facts===
-  * The Avogadro constant is $N_A = 6.022 \cdot 10^{23} \text{ mol}^{-1}$+  * The Avogadro constant is $N_A = 6.022 \cdot 10^{23} \text{ mol}^{-1}$. This is easy to look up, which is what we did.
     * Note: When we write the unit as $\text{ mol}^{-1}$, we mean particles per mole. We could also write this unit as $mol^{-1}=\frac{1}{mol}$.     * Note: When we write the unit as $\text{ mol}^{-1}$, we mean particles per mole. We could also write this unit as $mol^{-1}=\frac{1}{mol}$.
   * All electrons have the same charge, which is $e = -1.602\cdot10^{-19} \text{ C}$.   * All electrons have the same charge, which is $e = -1.602\cdot10^{-19} \text{ C}$.
  
-===Lacking=== +===Goal=== 
-  * Total Charge+  * Find the amount of charge in 1 mole of electrons.
  
-===Approximations & Assumptions=== 
-  * None, we have all the information we need. 
  
-===Representations=== 
-  * The total number of particles $N$ can be found from the number of moles $m$ using the Avogadro constant: $N = m \cdot N_A$. 
-  * The total charge $Q$ can be written as the number of particles $N$ times the charge of each particle ($e$, for electrons): $Q=N\cdot e$. 
 ====Solution==== ====Solution====
-The total number of electrons $N$ is given by+The total charge $Q$ can be written as the number of particles $N$ times the charge of each particle ($e$, for electrons): $Q=N\cdot e$. We know $e$, and since we know we are interested in exactly 1 mole, we can find $N$:
 \begin{align*} \begin{align*}
 N &= 1 \text{ mol} \cdot 6.022 \cdot 10^{23} \text{ mol}^{-1} \\ N &= 1 \text{ mol} \cdot 6.022 \cdot 10^{23} \text{ mol}^{-1} \\
  • 184_notes/examples/week2_moleoelectrons.txt
  • Last modified: 2018/05/17 15:16
  • by curdemma