184_notes:examples:week7_wire_dimensions

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184_notes:examples:week7_wire_dimensions [2017/10/04 13:41] – [Solution] tallpaul184_notes:examples:week7_wire_dimensions [2017/10/04 13:51] – [Solution] tallpaul
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 ====Solution==== ====Solution====
-Let's start with segment 1. The power dissipated through the segment is just $$P_1=I_1 \Delta V_1 = 5 \text{ W}$$ +Let's start with segment 1. The electric field is constant since the wire is uniform with respect to the rest of the segment, so we get $$E_1 = \frac{\Delta V_1}{L_1} = 0.5 \text{ V/m}$$ 
-The electric field is constant since the wire is uniform with respect to the rest of the segmentso we get $$E_1 = \frac{\Delta V_1}{L_1} = 0.5 \text{ V/m}$$+The power dissipated through the segment is just $$P_1=I_1 \Delta V_1 = 5 \text{ W}$$ 
 + 
 +Nowfor segment 2. We can use [[184_notes:r_energy#Conservation_of_Charge_in_Circuits|what we know]] about charge in steady state circuits to determine the electric field: $$E_2=\frac{A_1}{A_2}E_1 = \frac{\pi d_1^2}{\pi d_2^2}E_1=9E_1=4.5\text{ V/m}$$
  • 184_notes/examples/week7_wire_dimensions.txt
  • Last modified: 2021/06/14 23:40
  • by schram45