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184_notes:induced_current [2021/11/12 23:13] – [Step 2.) Draw the direction of the B-field through the relevant area] stumptyl | 184_notes:induced_current [2021/11/12 23:14] – [Step 5: Determining $V_{ind}$] stumptyl | ||
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Remember that the $d\vec{A}$ is perpendicular to the cross section area of the coils. Meaning, that you can think of the $d\vec{A}$ as pointing "out of” the coil. For our set up, this means that $d\vec{A}$ could point either to the left or right (-x or +x direction). It doesn' | Remember that the $d\vec{A}$ is perpendicular to the cross section area of the coils. Meaning, that you can think of the $d\vec{A}$ as pointing "out of” the coil. For our set up, this means that $d\vec{A}$ could point either to the left or right (-x or +x direction). It doesn' | ||
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====Step 4.) $\Phi_{B, | ====Step 4.) $\Phi_{B, | ||
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In our case, this means we'd be taking a small positive number minus a big positive number. This will result in a // | In our case, this means we'd be taking a small positive number minus a big positive number. This will result in a // | ||
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?440|Step 4: Determine the sign of the change in flux based on the initial and final flux for the situation. | ?440|Step 4: Determine the sign of the change in flux based on the initial and final flux for the situation. | ||
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For our example, the change in flux was negative. So we write down " | For our example, the change in flux was negative. So we write down " | ||
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?440|Step 5: The sign of the V-induced is the **opposite** of the change in flux. }}] | ?440|Step 5: The sign of the V-induced is the **opposite** of the change in flux. }}] | ||