184_notes:examples:week10_current_ring

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184_notes:examples:week10_current_ring [2021/07/07 17:38] – schram45184_notes:examples:week10_current_ring [2021/07/07 17:42] – schram45
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         &= \frac{\mu_0 I}{2R} \hat{z}         &= \frac{\mu_0 I}{2R} \hat{z}
 \end{align*} \end{align*}
 +<WRAP TIP>
 +===Assumption===
 +Assuming the current is steady allows us to take the $I$ out of the above integral, if this were not the case we would have to find out how current varies in the direction of $phi$ and leave it in the integral.
 +</WRAP>
  
 We show the visual result below. We show the visual result below.
  
 {{ 184_notes:10_ring_with_b.png?300 |Ring of Current, With Magnetic Field at Center}} {{ 184_notes:10_ring_with_b.png?300 |Ring of Current, With Magnetic Field at Center}}
  • 184_notes/examples/week10_current_ring.txt
  • Last modified: 2021/07/07 17:52
  • by schram45