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| Both sides previous revision Previous revision | Last revisionBoth sides next revision | ||
| 184_notes:examples:week10_current_ring [2021/07/07 17:42] – schram45 | 184_notes:examples:week10_current_ring [2021/07/07 17:42] – schram45 | ||
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| <WRAP TIP> | <WRAP TIP> | ||
| ===Assumption=== | ===Assumption=== | ||
| - | We assumed the current was flowing counterclockwise when the loop was viewed from the top. This means our current flows in the same direction as phi. If we had assumed a clockwise current flow then this value would just need a negative in front of it. | + | We assumed the current was flowing counterclockwise when the loop was viewed from the top. This means our current flows in the same direction as $\phi$. If we had assumed a clockwise current flow then this value would just need a negative in front of it. |
| </ | </ | ||
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| <WRAP TIP> | <WRAP TIP> | ||
| ===Assumption=== | ===Assumption=== | ||
| - | Assuming the current is steady allows us to take the $I$ out of the above integral, if this were not the case we would have to find out how current varies in the direction of $phi$ and leave it in the integral. | + | Assuming the current is steady allows us to take the $I$ out of the above integral, if this were not the case we would have to find out how current varies in the direction of $\phi$ and leave it in the integral. |
| </ | </ | ||