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| Both sides previous revision Previous revision Next revision | Previous revisionLast revisionBoth sides next revision | ||
| 184_notes:examples:week4_charge_cylinder [2021/06/29 18:01] – schram45 | 184_notes:examples:week4_charge_cylinder [2021/06/29 18:10] – schram45 | ||
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| &= \frac{Q\hat{x}}{4\pi\epsilon_0\left(z^2-\frac{L^2}{4}\right)} | &= \frac{Q\hat{x}}{4\pi\epsilon_0\left(z^2-\frac{L^2}{4}\right)} | ||
| \end{align*} | \end{align*} | ||
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| + | Since $z$ is very large we will once again eliminate any constant terms tied in with it.$$\vec{E} = \frac{1}{4\pi\epsilon_0}\frac{Q}{z^2}\hat{x}$$ | ||
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| + | As we can see this is exactly the equation we get for a point charge! This should be expected. When viewing charged objects from far away they can be approximated as points, kinda like looking at a person from a distance. | ||
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