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| Both sides previous revision Previous revision Next revision | Previous revisionLast revisionBoth sides next revision | ||
| 184_notes:examples:week5_gauss_ball [2021/06/07 13:54] – schram45 | 184_notes:examples:week5_gauss_ball [2021/06/07 14:00] – [Solution (Part A)] schram45 | ||
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| <WRAP TIP> | <WRAP TIP> | ||
| ===Assumptions=== | ===Assumptions=== | ||
| + | There are a few assumptions that can be made to simplify down our model before starting any calculations. | ||
| * There are no other charges that affect our calculations. | * There are no other charges that affect our calculations. | ||
| * The ball is not discharging. | * The ball is not discharging. | ||
| Line 78: | Line 79: | ||
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| \] | \] | ||
| - | Outside the ball, the electric field exists as if the ball were a point charge! | + | Outside the ball, the electric field exists as if the ball were a point charge! |
| ====Solution (Part B)==== | ====Solution (Part B)==== | ||
| We repeat the process above for the case that the ball is a conductor. Notice that much of the reasoning is the exact same. We still have spherical symmetry, and we choose the same Gaussian surface. It is pictured below for both $r<R$ and $r>R$. | We repeat the process above for the case that the ball is a conductor. Notice that much of the reasoning is the exact same. We still have spherical symmetry, and we choose the same Gaussian surface. It is pictured below for both $r<R$ and $r>R$. | ||