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184_notes:examples:week8_cap_parallel [2017/10/11 18:06] – [Solution] tallpaul | 184_notes:examples:week8_cap_parallel [2017/10/11 18:22] – [Connecting Already-Charged Capacitors] tallpaul | ||
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Suppose you have the following setup of already-charged capacitors. The positive plates are all on the top half of the circuit. Capacitors are labeled 1 through 3 for convenience of reference, and the sign of the charge on the plates is indicated. You know that $Q_1 = Q_2 = Q_3 = 1 \text{ mC}$, and $\Delta V_1 = \Delta V_2 = \Delta V_3 = 20 \text{ V}$. What is the equivalent capacitance (if the switches are closed) from Node A to Node B? What happens after the switches are closed? What if Capacitor 2 were flipped? | Suppose you have the following setup of already-charged capacitors. The positive plates are all on the top half of the circuit. Capacitors are labeled 1 through 3 for convenience of reference, and the sign of the charge on the plates is indicated. You know that $Q_1 = Q_2 = Q_3 = 1 \text{ mC}$, and $\Delta V_1 = \Delta V_2 = \Delta V_3 = 20 \text{ V}$. What is the equivalent capacitance (if the switches are closed) from Node A to Node B? What happens after the switches are closed? What if Capacitor 2 were flipped? | ||
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===Facts=== | ===Facts=== | ||
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* We represent the situation with diagram given above. The flipped situation is below. | * We represent the situation with diagram given above. The flipped situation is below. | ||
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====Solution==== | ====Solution==== | ||
All the charges and potential differences across the capacitors are the same, so they should have the same capacitance: | All the charges and potential differences across the capacitors are the same, so they should have the same capacitance: |