184_notes:ind_graphs

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184_notes:ind_graphs [2022/12/07 14:37] – valen176184_notes:ind_graphs [2022/12/07 14:39] – valen176
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     \end{cases}     \end{cases}
 $$ $$
-Which finally means that $V_{ind}$ is:+Now we can multiply by $-1$ because of the negative sign in Faraday's law to find $V_{ind}$:
 $$ $$
 V_{ind}= V_{ind}=
  • 184_notes/ind_graphs.txt
  • Last modified: 2022/12/07 14:43
  • by valen176