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repository:beating_the_train [2020/03/17 18:40] porcaro1 [See Also] |
repository:beating_the_train [2021/02/16 23:45] porcaro1 |
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| ====Activity==== | ====Activity==== | ||
| ===Handout=== | ===Handout=== | ||
| + | {{ :repository:beating_the_train1.png?nolink&600|}} | ||
| **Beating the Train**\\ | **Beating the Train**\\ | ||
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| A train is approaching a crossing, traveling at a constant velocity if 15 m/s to the east. You are on an afternoon ride on your motorcycle when you get stopped at a stoplight 50 m south of the crossing. At the instant the light turns green, the train is 90 m west of the crossing. Your mass, including the motorcycle, is 400 kg | A train is approaching a crossing, traveling at a constant velocity if 15 m/s to the east. You are on an afternoon ride on your motorcycle when you get stopped at a stoplight 50 m south of the crossing. At the instant the light turns green, the train is 90 m west of the crossing. Your mass, including the motorcycle, is 400 kg | ||
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| ====Answer Key==== | ====Answer Key==== | ||
| ===Handout=== | ===Handout=== | ||
| + | {{ :repository:beating_the_train2.png?nolink&600|}} | ||
| - To find the time it will take for the train to reach the crossing, divide the distance between the train and the crossing by the velocity of the train: | - To find the time it will take for the train to reach the crossing, divide the distance between the train and the crossing by the velocity of the train: | ||
| - $t=\dfrac{90\text{m}}{15\text{m/s}}=6\text{s}$ | - $t=\dfrac{90\text{m}}{15\text{m/s}}=6\text{s}$ | ||