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--- 183_notes:examples:averagevelcompare [2014/07/10 20:19] – caballero
+++ 183_notes:examples:averagevelcompare [2014/07/10 20:23] (current) – [Solution] caballero
@@ Line 40: / Line 40: @@
  $v_{avg,x} \approx \dfrac{v_i + v_f}{2} = \dfrac{24.6 \dfrac{m}{s} + 29.9 \dfrac{m}{s}}{2} = 27.3 \dfrac{m}{s}$
+You can see that the //arithmetic// average is (in this case) less than the average velocity. It also under-predicts how far you would have driven,
+ $\Delta x = v_{avg,x} \Delta t =  27.3 \dfrac{m}{s} (3600s+9000s) = 3.43\times10^5 m = 343 km$
+which is leaves you at the "outskirts" of Chicago (about 15  $km$  away).