Differences
This shows you the differences between two versions of the page.
| Both sides previous revision Previous revision Next revision | Previous revision | ||
| 183_notes:examples:deer_slug_example [2014/10/01 05:20] – pwirving | 183_notes:examples:deer_slug_example [2014/10/01 05:24] (current) – pwirving | ||
|---|---|---|---|
| Line 55: | Line 55: | ||
| 0=MG∗VG+mS∗VS⟶MG∗VG is negative and mS∗VS is positive (see diagram). | 0=MG∗VG+mS∗VS⟶MG∗VG is negative and mS∗VS is positive (see diagram). | ||
| + | |||
| + | To find the force acting on the shoulder of the shooter me need to know VG in order to find change in momentum for the gun and relate this to the force using →Fnet=Δ→pΔt. Rearrange the previous equation. | ||
| VG=−msMGVS | VG=−msMGVS | ||
| + | |||
| + | Fill in the values for the corresponding variables. | ||
| VG=−0.22kg3.5kg500m/s=−31.4m/s | VG=−0.22kg3.5kg500m/s=−31.4m/s | ||
| - | Need to find what kind of force that is on your shoulder. | + | Use the value found for VG to find the change in momentum and hence find what kind of force that is on your shoulder. |
| →Fnet=Δ→pΔt | →Fnet=Δ→pΔt | ||
| + | |||
| + | Fill in values for known variables. | ||
| →Fnet=(3.5kg)(−31.4m/s+0m/s)(1/24s) | →Fnet=(3.5kg)(−31.4m/s+0m/s)(1/24s) | ||