183_notes:examples:momentumfast

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183_notes:examples:momentumfast [2014/07/10 14:04] caballero183_notes:examples:momentumfast [2024/01/30 14:18] (current) – [Setup] hallstein
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 ====== Example: Calculating the momentum of a fast-moving object ====== ====== Example: Calculating the momentum of a fast-moving object ======
  
-An electron is observed to be moving with a velocity of $\langle 2.05\times10^7, 6.02\times10^7, 0\rangle\:\dfrac{m}{s}$. Determine the momentum of this electron.+An electron is observed to be moving with a velocity of $\langle -2.05\times10^7, 6.02\times10^7, 0\rangle\dfrac{m}{s}$. Determine the momentum of this electron.
  
 ==== Setup ==== ==== Setup ====
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   * An electron is in motion   * An electron is in motion
-  * It has a velocity of $\langle 2.05\times10^7, 6.02\times10^7, 0\rangle\:\dfrac{m}{s}$. +  * It has a velocity$\vec{v}_e=\langle -2.05\times10^7, 6.02\times10^7, 0\rangle\dfrac{m}{s}$. 
-  * This velocity is near the speed of light (c=3.00×108ms).+  * The speed of the electron is near the speed of light (c=3.00×108ms).
  
 === Lacking === === Lacking ===
  
-  * The mass of the electron is not given, but can be [[http://lmgtfy.com/?q=electron+mass|found online]] (me=9.11×1031kg).+  * The mass of the electron is not given, but can be [[https://en.wikipedia.org/wiki/Electron_mass|found online]] (me=9.11×1031kg).
  
 === Approximations & Assumptions === === Approximations & Assumptions ===
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 ==== Solution ==== ==== Solution ====
 +
 +First, we compute the speed of the electron.
 +
 +|ve|=v2x+v2y+v2z=(2.05×107ms)2+(6.02×107ms)2+(0)2=6.36×107ms
 +
 +Next, we compute the gamma factor.
 +
 +γ=11(|v|c)2=11(6.36×107ms3.00×108ms)2=11(0.212)2=1.02
 +
 +Finally, we compute the momentum vector.
 +
 +pe=γmeve=(1.02)(9.11×1031kg)2.05×107,6.02×107,0ms=1.91×1023,5.61×1023,0kgms
 +
  • 183_notes/examples/momentumfast.1405001043.txt.gz
  • Last modified: 2014/07/10 14:04
  • by caballero