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183_notes:examples:momentumfast [2014/07/10 14:10] – caballero | 183_notes:examples:momentumfast [2024/01/30 14:18] (current) – [Setup] hallstein | ||
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====== Example: Calculating the momentum of a fast-moving object ====== | ====== Example: Calculating the momentum of a fast-moving object ====== | ||
- | An electron is observed to be moving with a velocity of $\langle 2.05\times10^7, | + | An electron is observed to be moving with a velocity of $\langle |
==== Setup ==== | ==== Setup ==== | ||
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* An electron is in motion | * An electron is in motion | ||
- | * It has a velocity | + | * It has a velocity, $\vec{v}_e=\langle |
- | * This velocity | + | * The speed of the electron |
=== Lacking === | === Lacking === | ||
- | * The mass of the electron is not given, but can be [[http://lmgtfy.com/? | + | * The mass of the electron is not given, but can be [[https://en.wikipedia.org/ |
=== Approximations & Assumptions === | === Approximations & Assumptions === | ||
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First, we compute the speed of the electron. | First, we compute the speed of the electron. | ||
- | $$|\vec{v}| = \sqrt{v_x^2+v_y^2+v_z^2} = \sqrt{(2.05\times10^7 m/s)^2+(6.02\times10^7 m/s)^2+(0)^2} = 6.36e7 m/s$$ | + | $$|\vec{v}_e| = \sqrt{v_x^2+v_y^2+v_z^2} = \sqrt{(-2.05\times10^7 |
+ | |||
+ | Next, we compute the gamma factor. | ||
+ | |||
+ | γ=1√1−(|→v|c)2=1√1−(6.36×107ms3.00×108ms)2=1√1−(0.212)2=1.02 | ||
+ | |||
+ | Finally, we compute the momentum vector. | ||
+ | |||
+ | $$\vec{p}_e = \gamma m_e \vec{v}_e = (1.02) (9.11\times10^{-31} kg) \langle -2.05\times10^7, |