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--- 183_notes:examples:statictorque [2016/03/25 16:03] – klinkos1
+++ 183_notes:examples:statictorque [2016/03/25 16:04] (current) – klinkos1
@@ Line 31: / Line 31: @@
 Where r (show by h in this problem) is the distance between where the force is applied and the pivot of the system (the point it is rotating around), F is the amount of force, and  $\theta$  is the angle at which this force is applied.
 Now we can find the net torque of the system.
-Based on the diagram, we can determine that the pivot point of the system is at the keg, and the person turns around this. We can use this information to determine the radiuses of the three torques in our system. Torque due to the keg ( $\tau_{k}$ ), torque due to the support of the person ( $\tau_{p}$ ), and torque due to gravity ( $\tau_{g}$ ). The torque due to gravity will be negative since it acts in the opposite direction of the other two forces.
+Based on the diagram, we can determine that the pivot point of the system is at the keg, and the person turns around this. We can use this information to determine the radii of the three torques in our system. Torque due to the keg ( $\tau_{k}$ ), torque due to the support of the person ( $\tau_{p}$ ), and torque due to gravity ( $\tau_{g}$ ). The torque due to gravity will be negative since it acts in the opposite direction of the other two.
  $\tau_{net} = \tau_{k}+\tau_{p}-\tau_{g} = 0$
 The radius of the torque due to the keg is zero, since we established that the keg is at the pivot point. The radius of the torque due to the support of the person is the full length of the person being supported, since they are supported at their feet. The radius of the torque due to gravity is at half of the length of the supported person, since this is approximately their center of mass.