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183_notes:grav_accel [2014/09/10 02:16] – [The Gravitational Force and the Momentum Principle] caballero | 183_notes:grav_accel [2021/02/05 00:02] (current) – [The Gravitational Force and the Momentum Principle] stumptyl | ||
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+ | Section 3.2 and 3.3 in Matter and Interactions (4th edition) | ||
+ | |||
===== Gravitational Acceleration ===== | ===== Gravitational Acceleration ===== | ||
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→Fgrav=−Gm1m2|→r|2ˆr | →Fgrav=−Gm1m2|→r|2ˆr | ||
- | where object 1 has mass, m1, and object 2 has mass, m2. If the separation vector (→r) describes the relative position of object 2 with respect to object 1: | + | where object 1 has mass, m1, and object 2 has mass, m2. If the separation vector (→r) describes the relative position of object 2 with respect to object 1 (as shown in the figure to the right): |
→r=→r2−→r1 | →r=→r2−→r1 | ||
- | then the force expression above describes the force that object 1 exerts on object 2. That | + | then the force expression above describes the force that object 1 exerts on object 2. You can use [[183_notes: |
+ | |||
+ | →Fnet,2=Δ→p2Δt=→Fgrav,2 | ||
+ | |||
+ | Using the formula for each force, we find: | ||
+ | |||
+ | Δ→p2Δt=m2Δ→v2Δt=m2→a2=−Gm1m2|→r|2ˆr | ||
+ | |||
+ | We then divide the mass of the object 2 out (m2): | ||
+ | |||
+ | →a2=−Gm1|→r|2ˆr | ||
+ | |||
+ | //__The resulting expression is the acceleration that object 2 experiences due to it's gravitational interaction with object 1__//. Notice that the acceleration of object 2 depends only on the mass of object 1 (m1), and relative position of object 2 with respect to object 1 (→r). It also points towards object 1, which indicates that the object 2 is attracted (and will thus experience an acceleration along the line between object 1 and 2). | ||
+ | |||
+ | So, __in general__: | ||
+ | |||
+ | →a=−Gm|→r|2ˆr | ||
+ | |||
+ | Sometimes, it's useful to think of this acceleration occurring in a single dimension (e.g., along the line that connects object 1 and object 2). Let's take that line to line in the x-direction. In that case, the expression for the magnitude of the acceleration in x-direction is given by: | ||
+ | |||
+ | ax=−Gmx2 | ||
+ | |||
+ | where the object with mass m is the one that exerts the force on the mass in question (i.e., the object experiencing the acceleration) and x is the distance between the objects. | ||
+ | |||
+ | ==== The Local Gravitational Acceleration revisited ==== | ||
+ | |||
+ | Earlier you read that the [[183_notes: | ||
+ | |||
+ | For simplicity, let's take the downward vertical direction to be positive. Let's compute the acceleration due gravity at the surface of the Earth. Here the [[http:// | ||
+ | |||
+ | ay=GMEarthR2Earth=(6.67384×10−11m3kgs2)(5.97×1024kg(6.38×106m)2)=9.80ms2 | ||
+ | |||
+ | which is pretty close to the value we often use. In fact, the gravitational acceleration fluctuates a few percent over the surface of the Earth due to [[http:// |