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--- 184_notes:examples:week10_helix [2018/07/03 14:02] – curdemma
+++ 184_notes:examples:week10_helix [2021/07/07 15:42] (current) – schram45
@@ Line 15: / Line 15: @@
 ===Approximations & Assumptions===
   * The B-field is constant.
+  * Charge and Mass of the particle are constant.
 ===Representations===
@@ Line 30: / Line 31: @@
 So it seems like the motion here will not be circular. The magnetic force still plays a role, though because the velocity also has an x-component. From the magnetic force equation, we find that the magnetic force would be:
  $\vec{F}= q \vec{v} \times \vec{B} = = q (v_x \hat{x} + v_y \hat{y}) \times (B \hat{y}) = q v_x B \hat{z}$
+<WRAP TIP>
+===Assumptions===
+Our assumptions about the Constant B-Field and chrage are essential in simplifying down the force equation. If these assumptions were not true out force could also have some time and space dependency which would make solving for and predicting the force much more dificult.
+</WRAP>
 This force would still push the particle into a circular motion (while still not affecting the particle's motion in the y-direction.) So the particle would move in an upwards spiraling path.
 So when we look at the motion of the particle from the perspective of  $+y$  going into the page, we should see a circle with radius
  $r = \frac{mv_x}{qB} = 10 \text{ m}$
+<WRAP TIP>
+===Assumption===
+We assumed the mass was constant, and this allows for uniform circular motion in the x-z plane. If the mass were not constant then the path of the particle could look much different as the radius of curvature of the particle at any instance in time/space could change.
+</WRAP>
 However, because of the constant  $\hat{y}$  component of the velocity, this circle is actually a helix. Two perspectives show the motion below.
 [{{ 184_notes:10_helical_motion.png?600 |Motion of the Moving Charge}}]