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184_notes:examples:week12_moving_coils_flux [2017/11/10 17:31] – created tallpaul | 184_notes:examples:week12_moving_coils_flux [2018/04/11 19:36] (current) – [Solution] pwirving | ||
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===== Flux Through Moving Coils ===== | ===== Flux Through Moving Coils ===== | ||
- | Say we have a bar that is sliding down a pair of connected conductive rails (so current | + | Suppose you have two conducting rings centered on the same axis so that they face one another. One of the rings has a current |
===Facts=== | ===Facts=== | ||
- | * The magnetic | + | * The rings are oriented so that there is a magnetic |
- | * The loop is oriented so that the magnetic flux is nonzero. | + | * There is only current in the first ring. |
===Lacking=== | ===Lacking=== | ||
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===Approximations & Assumptions=== | ===Approximations & Assumptions=== | ||
- | * The magnetic field is constant | + | * There is no current |
- | * The sliding of the bar along the rails happens | + | * There is no power source for the first ring's current, and so it is free to change |
===Representations=== | ===Representations=== | ||
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* We represent the steps with the following visual: | * We represent the steps with the following visual: | ||
- | {{ 184_notes:12_rail_flux.png?400 |Flux Through Loop}} | + | {{ 184_notes:12_coils.png?400 |Two Coils}} |
====Solution==== | ====Solution==== | ||
- | Since the magnetic field has a uniform direction, and the area of the loop is flat (meaning $\text{d}\vec{A}$ does not change | + | Before any motion happens, we can look at the rings from a side view, and represent |
- | $$\int \vec{B} \bullet \text{d}\vec{A} = \int B\text{d}A\cos\theta$$ | + | |
- | Since $B$ and $\theta$ do not change for different little pieces ($\text{d}A$) of the area, we can pull them outside the integral: | + | {{ 184_notes:12_coils_field.png? |
- | $$\int B\text{d}A\cos\theta =B\cos\theta \int \text{d}A = BA\cos\theta$$ | + | When the rings begin to move towards one another, you can imagine that the second ring experiences an increase in magnetic flux, since the magnetic field is stronger closer to the ring with current. When we say the flux " |
- | It will be easier to concern ourselves with this value, rather than try to describe | + | Since the flux is increasing, we expect |
- | {{ 184_notes:12_rail_flux_decreased.png?400 |Decreased Flux}} | + | {{ 184_notes:12_coils_induced_current.png?400 |Induced Current}} |
- | It should be easy to see the that the magnetic field and the orientation of the loop are not changing, but the area of the loop is decreasing. The flux through the loop is therefore decreasing, which indicates | + | In fact, this induced current and resulting |
- | To determine the direction of the current, consider that when we say the flux decreases, this carries the assumption that the area vector points in the same direction as the magnetic field, which is into the page. The induced current should create a magnetic field that opposes the change in flux. The change in flux is a " | + | {{youtube> |
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- | Alternatively, | + | |
- | + | ||
- | {{ 184_notes: | + |