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184_notes:examples:week3_balloon_wall [2017/08/28 19:43] – [Example: Balloon Stuck to a Wall] tallpaul | 184_notes:examples:week3_balloon_wall [2021/01/26 21:21] (current) – [Solution] bartonmo | ||
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+ | [[184_notes: | ||
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=====Example: | =====Example: | ||
- | When you rub part of a rubber balloon against wool, electrons will leave the wool, which is slightly conductive, and go onto the balloon. The rubber on the balloon is much less conductive (rubber is more of an insulator than wool), and the electrons will not readily leave the balloon. As a result, the balloon becomes negatively charged. Imagine you bring the negatively charged balloon up to a wall, and it sticks (This is possible! A quick internet search will yield many explanations and demonstrations. You can also try it yourself). Draw a force diagram for the balloon. | + | When you rub part of a rubber balloon against wool (or your hair), electrons will leave the wool, which is slightly conductive, and go onto the balloon. The rubber on the balloon is much less conductive (rubber is more of an insulator than wool), and the electrons will not readily leave the balloon. As a result, the balloon becomes negatively charged. Imagine you bring the negatively charged balloon up to a wall, and it sticks (This is possible! A quick internet search will yield many explanations and demonstrations. You can also try it yourself). |
===Facts=== | ===Facts=== | ||
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* The balloon is stuck to the wall. | * The balloon is stuck to the wall. | ||
- | ===Lacking=== | + | ===Representations=== |
- | * The specific charge distribution on the balloon. | + | <WRAP TIP> |
- | * The electric properties of the wall. | + | === Assumptions === |
- | * The force diagram. | + | We need to make a few assumptions to simplify our representation. |
- | + | ||
- | ===Approximations & Assumptions=== | + | |
- | | + | |
- | * The wall is a perfect insulator, and is neutral. | + | |
* The balloon is motionless. | * The balloon is motionless. | ||
* The balloon is touching the wall at exactly one point. | * The balloon is touching the wall at exactly one point. | ||
* The wall is perfectly vertical (parallel to the gravitational force). | * The wall is perfectly vertical (parallel to the gravitational force). | ||
- | * The interaction between the wall and the extra negative charges on the balloon is much stronger than the interaction between the wall and any polarized atoms in the balloon. For this reason, we choose | + | </ |
+ | [{{ 184_notes: | ||
- | ===Representations=== | + | ===Goal=== |
- | * It will help to draw a diagram of the balloon | + | * Find a way to explain why the balloon |
- | * As usual, we represent polarized atoms in an insulator with little ovals. | + | |
- | * We can represent the forces on the balloon with a force diagram. This is also given in the solution. | + | |
====Solution==== | ====Solution==== | ||
- | Based on our Approximations and Assumptions, | ||
- | {{ 184_notes: | ||
- | The atoms in the wall near to the balloon are polarized in this way because of the negative charge in the balloon. See the notes on [[184_notes: | ||
- | We know the balloon is motionless, so air resistance is not a factor here, as it often is with balloons. | + | We observe the balloon stuck motionless to the wall. If we want to draw a free body diagram to analyze the forces, we know that the net force must be zero. If we had to list out the forces, we could start with gravity. That will point straight down. Also, since the balloon is up against the wall, there must be a normal force from the wall, too. To simplify our model, we make an assumption: |
- | {{ 184_notes: | + | <WRAP TIP> |
+ | === Assumption === | ||
+ | We assume that there is no appreciable force of friction between the wall and the balloon. This assumption is not absolutely necessary -- depending on what you think of the other forces at play, friction may or may not play a role. For our solution, we do not use friction, since we think it makes the discussion a little simpler. | ||
+ | </ | ||
+ | |||
+ | We know the balloon is motionless, so air resistance is not a factor here, as it often is with balloons. | ||
+ | |||
+ | [{{ 184_notes: | ||
+ | |||
+ | In order to describe how we might get this diagonal electric force, we'll make a few more assumptions. | ||
+ | |||
+ | <WRAP TIP> | ||
+ | === Assumptions === | ||
+ | We assume two things about the charges in the balloon and in the wall: | ||
+ | * The balloon is not very conductive, so the electrons from the wool are stuck where they are. We'll say they are distributed near the part of the balloon close to the wall. | ||
+ | * The wall is a perfect insulator, and is neutral. | ||
+ | We make the first assumption about the balloon because it will be easier to see where the electric | ||
+ | </ | ||
+ | |||
+ | With these assumptions in mind, it's reasonable to say that the interaction between the wall and the extra negative charges on the balloon is much stronger than the interaction between the wall and any polarized atoms in the balloon. For this reason, we can ignore polarized atoms in the balloon. This seems reasonable, since a balloon will not stick to a wall without having rubbed the balloon with something that will transfer some of its electrons to the balloon. | ||
+ | |||
+ | We can use the following representation, | ||
+ | [{{ 184_notes: | ||
+ | |||
+ | We know that the balloon is negatively charged | ||
+ | |||
+ | Notice that the electric force needs to point both to the left and upward in order for the net force to be zero. If you were to try this experiment out yourself, you may notice the balloon rolling slightly up and down (oscillating) before settling to a motionless state. As the balloon rolls, the charge distribution on the balloon moves in the same way that the balloon does, which changes the direction of the electric force on the balloon from the wall. When the balloon settles, we know it has come to a place where the direction and magnitude of the electric force results in a net force of zero. | ||
+ | |||
+ | //Another note on our assumption about friction//: We do not include friction in the force diagram. We assume |