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--- 184_notes:examples:week4_charge_cylinder [2021/06/29 18:07] – schram45
+++ 184_notes:examples:week4_charge_cylinder [2021/07/22 18:21] (current) – schram45
@@ Line 12: / Line 12: @@
 ===Goal===
   * Find the electric field at  $P$ .
+===Assumptions===
+  * This is a perfect cylinder: This simplifies down the geometry of the problem and allows us to use any equations related to the geometry of the cylinder
+  * There is no top or bottom: We make this assumption so that we can break the cylinder up into rings and not have to do anything with the top or bottom sides of the cylinder (essentially we are dealing with a 2D tube).
 ===Representations===
@@ Line 74: / Line 78: @@
 \end{align*}
-Since  $z$  is very large we will once again eliminate any constant terms tied in with it. $vec{E} = \frac{1}{4\pi\epsilon_0}\frac{Q}{z^2}\hat{x}$
+Since  $z$  is very large we will once again eliminate any constant terms tied in with it.$$\vec{E} = \frac{1}{4\pi\epsilon_0}\frac{Q}{z^2}\hat{x}$$
+As we can see this is exactly the equation we get for a point charge! This should be expected. When viewing charged objects from far away they can be approximated as points, kinda like looking at a person from a distance.