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--- 184_notes:examples:week5_gauss_ball [2021/06/07 13:54] – schram45
+++ 184_notes:examples:week5_gauss_ball [2021/06/07 14:02] (current) – schram45
@@ Line 23: / Line 23: @@
 <WRAP TIP>
 ===Assumptions===
+There are a few assumptions that can be made to simplify down our model before starting any calculations.
   * There are no other charges that affect our calculations.
   * The ball is not discharging.
@@ Line 78: / Line 79: @@
          \end{cases}
 \]
-Outside the ball, the electric field exists as if the ball were a point charge!
+Outside the ball, the electric field exists as if the ball were a point charge! It is also important to note that the relationships seen in our above equations also agree with what we already know about insulating spheres of charge.
 ====Solution (Part B)====
 We repeat the process above for the case that the ball is a conductor. Notice that much of the reasoning is the exact same. We still have spherical symmetry, and we choose the same Gaussian surface. It is pictured below for both  $r<R$  and  $r>R$ .