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--- 184_notes:examples:week8_resistors_series [2021/06/28 23:33] – schram45
+++ 184_notes:examples:week8_resistors_series [2021/07/05 21:45] (current) – [Solution] schram45
@@ Line 55: / Line 55: @@
  $P_2=I^2R_2= 0.5 \text{ W}$
-One way in which we can evaluate our solution in this problem is by seeing if the power generated by the battery is equal to the power dissipated through the resistors.
+One way in which we can evaluate our solution in this problem is by seeing if the power generated by the battery is equal to the power dissipated through the resistors. You will find that the 1.2 Watts of power generated by the battery is completely dissipated through the resistors.
 \begin{align*}
- $$P<sub>gen</sub>=P<sub>dis</sub>$$
+P_{gen} &= P_{dis} \\
+I\Delta V_{bat} &= P_1 + P_2 + P_3 \\
+I\Delta V_{bat} &= P_1 + P_2 + I\Delta V_3 \\
+.1\left(12\right) &= 0.1 + 0.5 + 0.1\left(6\right) \\
+.2 &= 1.2
 \end{align*}