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184_notes:kirchoffs_rules [2018/10/04 13:55] – dmcpadden | 184_notes:kirchoffs_rules [2022/02/21 21:52] (current) – [Step 3: Identify the Loops and write out the Loop Rule equations] dmcpadden | ||
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===== Using Loop and Node Rules to Solve Circuits ===== | ===== Using Loop and Node Rules to Solve Circuits ===== | ||
- | So far this week, we have talked about how to deal with circuit elements that are in series and in parallel. We can use these rules for resistance, along with Ohm's law, to figure out the current and voltage at every point in the circuit. However, how do you solve circuits that are neither in series or parallel? Or when there are multiple voltage sources? For circuits that don't follow the series/ | + | So far this week, we have talked about how to deal with circuit elements that are in [[184_notes: |
==== Example and Steps for Node/Loop Rules ==== | ==== Example and Steps for Node/Loop Rules ==== | ||
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==== Step 1: Pick the direction of current in each branch of the circuit ==== | ==== Step 1: Pick the direction of current in each branch of the circuit ==== | ||
- | {{ 184_notes: | + | [{{ 184_notes: |
- | The first thing we need to do when solving these problems is to pick a direction for the current in each branch of the circuit. This is very similar to picking a coordinate system, just in the context of circuits. In the circuit below, we have picked the directions for the currents labeled now as I1, I2, and I3. You can pick which ever directions you want in this step. For example, we could have picked I3 to point up instead of down (or similarly for the other currents). It doesn' | + | The first thing we need to do when solving these problems is to pick a direction for the current in each branch of the circuit. This is very similar to picking a coordinate system, just in the context of circuits. In the circuit below, we have picked the directions for the currents labeled now as I1, I2, and I3. You can pick which ever directions you want in this step. For example, we could have picked I3 to point up instead of down (or similarly for the other currents). |
==== Step 2: Identify the Nodes and write out the Node Rule equations ==== | ==== Step 2: Identify the Nodes and write out the Node Rule equations ==== | ||
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For the Node equations, you want to pick the junctions where you have more than one current either entering or leaving that junction. For our example, this would be Point B and Point E. Then we use the Conservation of Charge to say that Iin=Iout for that junction (i.e. all of the charge that enters that point must also leave that point). For Point B, this equation would then be: | For the Node equations, you want to pick the junctions where you have more than one current either entering or leaving that junction. For our example, this would be Point B and Point E. Then we use the Conservation of Charge to say that Iin=Iout for that junction (i.e. all of the charge that enters that point must also leave that point). For Point B, this equation would then be: | ||
- | $$\text{Node B: } I_1+I_2=I_3$$ | + | $$\text{Node B: } I_1 = I_2+I_3$$ |
and for Point E, this equation would be: | and for Point E, this equation would be: | ||
- | $$\text{Node E: } I_3=I_1+I_2$$ | + | $$\text{Node E: } I_3+I_2=I_1$$ |
You'll notice that the Node equations for Points B and E are exactly the same (just flipped as to which currents are going " | You'll notice that the Node equations for Points B and E are exactly the same (just flipped as to which currents are going " | ||
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The next step is to identify the loops in the circuit, then use the Loop Rule to write an equation for each of those loops. In the example circuit, there are three distinct loops: | The next step is to identify the loops in the circuit, then use the Loop Rule to write an equation for each of those loops. In the example circuit, there are three distinct loops: | ||
- | {{ 184_notes: | + | [{{ 184_notes: |
1) one loop that goes around the left part of the circuit (A→B→E→D→A) | 1) one loop that goes around the left part of the circuit (A→B→E→D→A) | ||
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3) one loop that goes around the right part of the circuit (B→C→F→E→B) | 3) one loop that goes around the right part of the circuit (B→C→F→E→B) | ||
- | It doesn' | + | It doesn' |
* For batteries, the positive and negative sides are indicated by the length of the line (the longer line is the positive side, the shorter line is the negative side). | * For batteries, the positive and negative sides are indicated by the length of the line (the longer line is the positive side, the shorter line is the negative side). | ||
- | | + | * For resistors, the positive and negative sides are indicated by the **current directions |
* For capacitors, they will either come pre-labeled which indicate which side is positive/ | * For capacitors, they will either come pre-labeled which indicate which side is positive/ | ||
For our circuit, the positive/ | For our circuit, the positive/ | ||
- | {{ 184_notes: | + | [{{ 184_notes: |
We are now ready to write out the three loop equations: | We are now ready to write out the three loop equations: | ||
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Loop ABEDA: −ΔVβ−ΔVδ+ΔV1=0 | Loop ABEDA: −ΔVβ−ΔVδ+ΔV1=0 | ||
- | $$\text{Loop BCFEB: | + | $$\text{Loop BCFEB: |
- | $$\text{Loop ABCFEDA: | + | $$\text{Loop ABCFEDA: |
Once you have the loop equations written out, you can always substitute ΔV=IR to make better use of your knowns/ | Once you have the loop equations written out, you can always substitute ΔV=IR to make better use of your knowns/ | ||
- | $$\text{Loop ABEDA: | + | $$\text{Loop ABEDA: |
Since this form of the equation better relates the unknown currents with the known resistor values and battery voltages. | Since this form of the equation better relates the unknown currents with the known resistor values and battery voltages. | ||