184_notes:examples:week2_moleoelectrons

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How much total charge (in coulombs) is in one mole ($n=6.022*10^{23} \text{ particles/mol}$) of electrons?

Facts

  • $1 \text{ mol} = 6.022 \cdot 10^{23} \text{ particles}$
  • All electrons have the same charge, which is $e$ = $-1.602\cdot10^{-19} \text{ C}$.

Lacking

  • Total Charge

Approximations & Assumptions

  • None here, we have all the information we need.

Representations

  • The total charge $Q$ can be written as the number of particles $N$ times the charge of each particle ($e$, for electrons): $Q=N\cdot e$.

The total charge $Q$ is given by \begin{align*} Q &= N \cdot e \\ &= 1 \text{ mol} \cdot 1.602*10^{19} \text{ C} \\ &= \end{align*} The number of electrons in one mole is obtained by multiplying the number of moles by Avogodro's number. $$N=(1 mole)*6.022*10^{23}$$ $$N=6.022*10^{23} electrons$$ Therefore, the total charge $Q$ is given by… $$Q=N*e$$ $$Q=(6.022*10^{23})*(1.602*10^{19} C)$$ $$Q=96472.44 C$$

  • 184_notes/examples/week2_moleoelectrons.1503594709.txt.gz
  • Last modified: 2017/08/24 17:11
  • by tallpaul