184_notes:examples:week2_moleoelectrons

Differences

This shows you the differences between two versions of the page.

Link to this comparison view

Both sides previous revision Previous revision
Next revision
Previous revision
184_notes:examples:week2_moleoelectrons [2017/08/24 17:19] – [Example: How much total charge is in one mole of electrons?] tallpaul184_notes:examples:week2_moleoelectrons [2018/05/17 15:16] (current) curdemma
Line 1: Line 1:
- +[[184_notes:charge|Return to Electric Charge Page]] 
-===== Example: How much total charge is in one mole of electrons=====+===== Example: Find the total charge for a mole of electrons =====
 How much total charge (in coulombs) is in one mole of electrons? How much total charge (in coulombs) is in one mole of electrons?
  
 ===Facts=== ===Facts===
-  * The Avogadro constant is $6.022 \cdot 10^{23} \text{ mol}^{-1}$ +  * The Avogadro constant is $N_A = 6.022 \cdot 10^{23} \text{ mol}^{-1}$. This is easy to look up, which is what we did. 
-    * Note: When we write the unit as $\text{ mol}^{-1}$, we mean particles per mole. +    * Note: When we write the unit as $\text{ mol}^{-1}$, we mean particles per mole. We could also write this unit as $mol^{-1}=\frac{1}{mol}$
-  * All electrons have the same charge, which is $e$-1.602\cdot10^{-19} \text{ C}$.+  * All electrons have the same charge, which is $e = -1.602\cdot10^{-19} \text{ C}$.
  
-===Lacking=== +===Goal=== 
-  * Total Charge+  * Find the amount of charge in 1 mole of electrons.
  
-===Approximations & Assumptions=== 
-  * None here, we have all the information we need. 
  
-===Representations=== 
-  * The total charge $Q$ can be written as the number of particles $N$ times the charge of each particle ($e$, for electrons): $Q=N\cdot e$. 
 ====Solution==== ====Solution====
-The total number of electrons $N$ is given by+The total charge $Q$ can be written as the number of particles $N$ times the charge of each particle ($e$, for electrons): $Q=N\cdot e$. We know $e$, and since we know we are interested in exactly 1 mole, we can find $N$:
 \begin{align*} \begin{align*}
 N &= 1 \text{ mol} \cdot 6.022 \cdot 10^{23} \text{ mol}^{-1} \\ N &= 1 \text{ mol} \cdot 6.022 \cdot 10^{23} \text{ mol}^{-1} \\
   &= 6.022 \cdot 10^{23}   &= 6.022 \cdot 10^{23}
 \end{align*} \end{align*}
-The total charge $Q$ is given by+We now have $N$ and $e$. The total charge $Q$ is then given by
 \begin{align*} \begin{align*}
 Q &= N \cdot e \\ Q &= N \cdot e \\
   &= 6.022 \cdot 10^{23} \cdot -1.602 \cdot 10^{-19} \text{ C} \\   &= 6.022 \cdot 10^{23} \cdot -1.602 \cdot 10^{-19} \text{ C} \\
-  &= 9.647 \cdot 10^4 \text{ C}+  &-9.647 \cdot 10^4 \text{ C}
 \end{align*} \end{align*}
  • 184_notes/examples/week2_moleoelectrons.1503595190.txt.gz
  • Last modified: 2017/08/24 17:19
  • by tallpaul