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184_notes:examples:week8_wheatstone [2021/06/29 00:17] – [Solution (Part B)] schram45 | 184_notes:examples:week8_wheatstone [2021/07/22 18:28] (current) – schram45 | ||
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[{{ 184_notes: | [{{ 184_notes: | ||
- | To find $\Delta V_{\text{light}}$, | + | To find $\Delta V_{\text{light}}$, |
[{{ 184_notes: | [{{ 184_notes: | ||
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Applying the Node Rule and the Loop Rule, we obtain the following equations: | Applying the Node Rule and the Loop Rule, we obtain the following equations: | ||
\begin{align*} | \begin{align*} | ||
- | I &= I_1 + I_2 & | + | I &= I_1 + I_2 & |
- | I &= I_3 + I_4 & | + | I &= I_3 + I_4 & |
\Delta V_{\text{bat}} &= \Delta V_1 + \Delta V_3 & | \Delta V_{\text{bat}} &= \Delta V_1 + \Delta V_3 & | ||
\Delta V_{\text{bat}} &= \Delta V_2 - \Delta V_{\text{light}} + \Delta V_3 & | \Delta V_{\text{bat}} &= \Delta V_2 - \Delta V_{\text{light}} + \Delta V_3 & | ||
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$$\Delta V_{\text{light}} = \frac{\Delta V_3\left(\frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4}\right) - \Delta V_{\text{bat}}\left(\frac{1}{R_1} + \frac{1}{R_2}\right)}{\frac{1}{R_2} + \frac{1}{R_4}} = 2.37 \text{ V}$$ | $$\Delta V_{\text{light}} = \frac{\Delta V_3\left(\frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \frac{1}{R_4}\right) - \Delta V_{\text{bat}}\left(\frac{1}{R_1} + \frac{1}{R_2}\right)}{\frac{1}{R_2} + \frac{1}{R_4}} = 2.37 \text{ V}$$ | ||
- | Just looking | + | Looking |