184_notes:i_b_force

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184_notes:i_b_force [2020/08/23 22:21] – dmcpadden184_notes:i_b_force [2021/07/13 11:58] (current) – schram45
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 {{youtube>cz3Q22KW7fs?large}} {{youtube>cz3Q22KW7fs?large}}
-==== Force on a little chunk ====+===== Force on a little chunk =====
 If we think about a long straight wire with a //__steady state current__//, we can model this simply as many moving charges in a wire. When that wire is placed in an external magnetic field (from some other source - either another wire or permanent magnet), each of the moving charges would feel a force. Collectively, this results in a net force on the wire by the magnetic field.  If we think about a long straight wire with a //__steady state current__//, we can model this simply as many moving charges in a wire. When that wire is placed in an external magnetic field (from some other source - either another wire or permanent magnet), each of the moving charges would feel a force. Collectively, this results in a net force on the wire by the magnetic field. 
  
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 using the fact that $\frac{dq}{dt}$ is the definition of conventional current (the amount of charge passing a point per second).  using the fact that $\frac{dq}{dt}$ is the definition of conventional current (the amount of charge passing a point per second). 
  
-[{{  184_notes:week11_7.png?350|Magnetic Force produced on a current carrying wire in an external magnetic field}}]+[{{  184_notes:week11_7.png?350|Magnetic Force, F, produced on a current carrying wire in an external magnetic field, B}}]
 This means that the small amount of force on the wire is given by: This means that the small amount of force on the wire is given by:
 $$d\vec{F}= I d\vec{l} \times \vec{B}$$ $$d\vec{F}= I d\vec{l} \times \vec{B}$$
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 Note: that the force is still given by the cross product between the $d\vec{l}$ and the $\vec{B}$, so the force on the piece of wire is //still// perpendicular to both the direction of the moving charges ($d\vec{l}$) and perpendicular to the magnetic field ($\vec{B}$). This means we can still use the [[184_notes:rhr|right hand rule]] to figure out the direction of the $d\vec{F}$. Note: that the force is still given by the cross product between the $d\vec{l}$ and the $\vec{B}$, so the force on the piece of wire is //still// perpendicular to both the direction of the moving charges ($d\vec{l}$) and perpendicular to the magnetic field ($\vec{B}$). This means we can still use the [[184_notes:rhr|right hand rule]] to figure out the direction of the $d\vec{F}$.
    
-==== Force on the whole wire ====  +===== Force on the whole wire ===== 
-Now that we have the magnetic force on a small piece of the wire, we can find the total force on the wire from the external magnetic field by adding up the contributions from each little piece of the wire. Since we have the small bit of force from the small bit of wire, we will add these using a integral:+Now that we have the magnetic force on a small piece of the wire, we can find the total force on the wire from the external magnetic field by adding up the contributions from each little piece of the wire. Since we have the small bit of force from the small bit of wire, we will add these using an integral:
 $$\vec{F}_{wire}= \int_{wire} d\vec{F} = \int_{l_i}^{l_f} I d\vec{l} \times \vec{B}$$ $$\vec{F}_{wire}= \int_{wire} d\vec{F} = \int_{l_i}^{l_f} I d\vec{l} \times \vec{B}$$
 Here we want to pick the limits of the integral to be from the starting point of the wire ($l_i$) to the end of the wire ($l_f$) so we are adding up over the whole length of the wire. This form of the force will //always// work to find the magnetic force on the whole wire - we have not made very many assumptions so far in coming up with this equation.  Here we want to pick the limits of the integral to be from the starting point of the wire ($l_i$) to the end of the wire ($l_f$) so we are adding up over the whole length of the wire. This form of the force will //always// work to find the magnetic force on the whole wire - we have not made very many assumptions so far in coming up with this equation. 
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 $$|\vec{F}_{wire}|=IBLsin(\theta)$$ $$|\vec{F}_{wire}|=IBLsin(\theta)$$
  
-[{{  184_notes:week11_8.png?250|Use the right hand rule to determine the direction of the magnetic force}}]+[{{  184_notes:week11_8.png?250|Use the right hand rule to determine the direction of the magnetic force F}}]
  
 where |$\vec{F}_{wire}$| is the magnitude of the force on the whole wire, $I$ is the current through the wire, $B$ is the //external// magnetic field, $L$ is the length of the wire, and $\theta$ is the angle between the magnetic field and the length of the wire. //__Remember though that this equation is only good for straight wires with constant current that are in a constant magnetic field - because of all the assumptions that we made to get to this point.__// where |$\vec{F}_{wire}$| is the magnitude of the force on the whole wire, $I$ is the current through the wire, $B$ is the //external// magnetic field, $L$ is the length of the wire, and $\theta$ is the angle between the magnetic field and the length of the wire. //__Remember though that this equation is only good for straight wires with constant current that are in a constant magnetic field - because of all the assumptions that we made to get to this point.__//
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 ==== Examples ==== ==== Examples ====
-[[:184_notes:examples:Week12_force_between_wires|Magnetic Force between Two Current-Carrying Wires]] +  * [[:184_notes:examples:Week12_force_between_wires|Magnetic Force between Two Current-Carrying Wires]] 
- +    * Video Example: Magnetic Force between Two Current-Carrying Wires 
-[[:184_notes:examples:Week12_force_loop_magnetic_field|Force on a Loop of Current in a Magnetic Field]]+  * [[:184_notes:examples:Week12_force_loop_magnetic_field|Force on a Loop of Current in a Magnetic Field]] 
 +    * Video Example: Force on a Loop of Current in a Magnetic Field 
 +{{youtube>BLuU7nZWv5k?large}} 
 +{{youtube>jMoOVHU6RR0?large}}
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