Differences

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--- course_planning:183_projects:f17_project_15_solution [2017/12/07 00:46] – pawlakal
+++ course_planning:183_projects:f17_project_15_solution [2017/12/07 00:48] (current) – pawlakal
@@ Line 10: / Line 10: @@
 $$w=7.42 rad/s$$
-We can use $$v=rw$$ to convert this to the linear speed that the steel ball leaves the catapult with:
+We can use $v=rw$ to convert this to the linear speed that the steel ball leaves the catapult with:
 $$v_{i, steel}=(4 m)*(7.42 rad/s)$$
-$$v_{i, steel}=29.68$$
+$$v_{i, steel}=29.68 m/s$$
 Now we use energy conservation and linear momentum conservation to consider the collision between the steel ball and the shark. We take our system to be the shark and steel ball, and we assume that the shark starts at rest. We also assume that the collision is elastic. For momentum conservation, we get:
@@ Line 45: / Line 45: @@
   * **Question:**  What assumptions did you make?
-  * **Expected Answer:**  The water exerts no force resisting the shark's recoil. That gravity doesn't accelerate the steel ball its way from the catapult to the shark. That the steel ball experiences no air resistance. That the clay ball hits the catapult perpendicular to its arm. That the shark-steel ball collision is elastic.
+  * **Expected Answer:**  The water exerts no force resisting the shark's recoil. That gravity doesn't accelerate the steel ball its way from the catapult to the shark. That the steel ball experiences no air resistance. That the clay ball hits the catapult perpendicular to its arm at the very end of the arm. That the shark-steel ball collision is elastic.
+</WRAP>