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| Both sides previous revision Previous revision Next revision | Previous revision | ||
| course_planning:183_projects:f17_project_15_solution [2017/12/07 00:48] – pawlakal | course_planning:183_projects:f17_project_15_solution [2017/12/07 00:48] (current) – pawlakal | ||
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| $$w=7.42 rad/s$$ | $$w=7.42 rad/s$$ | ||
| - | We can use $$v=rw$$ to convert this to the linear speed that the steel ball leaves the catapult with: | + | We can use $v=rw$ to convert this to the linear speed that the steel ball leaves the catapult with: |
| $$v_{i, steel}=(4 m)*(7.42 rad/s)$$ | $$v_{i, steel}=(4 m)*(7.42 rad/s)$$ | ||
| - | $$v_{i, steel}=29.68$$ | + | $$v_{i, steel}=29.68 |
| Now we use energy conservation and linear momentum conservation to consider the collision between the steel ball and the shark. We take our system to be the shark and steel ball, and we assume that the shark starts at rest. We also assume that the collision is elastic. For momentum conservation, | Now we use energy conservation and linear momentum conservation to consider the collision between the steel ball and the shark. We take our system to be the shark and steel ball, and we assume that the shark starts at rest. We also assume that the collision is elastic. For momentum conservation, | ||