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184_notes:amp_law [2018/07/24 14:27] – [Magnetic Field Outside a Long Straight Wire] curdemma184_notes:amp_law [2020/08/24 13:29] (current) – dmcpadden
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 Section 21.6 in Matter and Interactions (4th edition) Section 21.6 in Matter and Interactions (4th edition)
  
-[[184_notes:i_thru|Previous Page: Current through a Loop]]+/*[[184_notes:i_thru|Previous Page: Current through a Loop]]*/
  
 ===== Putting Ampere's Law together ===== ===== Putting Ampere's Law together =====
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 $$\oint \vec{B} \bullet d\vec{l} = \mu_0 I_{enc}$$ $$\oint \vec{B} \bullet d\vec{l} = \mu_0 I_{enc}$$
  
-{{  184_notes:week10_6.png?600}}+[{{  184_notes:week10_6.png?600|Amperian loop of radius, $R$, around a wire with current, $I$}}]
  
 For the left hand side, we argued the magnetic field curls around the wire. So long as the wire has a uniform steady current, that magnitude of that magnetic field will be constant at any fixed distance from the wire. This lead us to derive the left-hand side of Ampere's Law for an Amperian loop of radius $R$ centered on the wire, For the left hand side, we argued the magnetic field curls around the wire. So long as the wire has a uniform steady current, that magnitude of that magnetic field will be constant at any fixed distance from the wire. This lead us to derive the left-hand side of Ampere's Law for an Amperian loop of radius $R$ centered on the wire,
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 This is [[184_notes:b_current#Magnetic_Field_from_a_very_long_wire|exactly the result we obtained with Biot-Savart for a very long wire]] (but we had to do a much more complicated integral).  This is [[184_notes:b_current#Magnetic_Field_from_a_very_long_wire|exactly the result we obtained with Biot-Savart for a very long wire]] (but we had to do a much more complicated integral). 
  
-Something that is important to ask is what is the direction of this B-field? With Ampere's Law, our magnetic field vector turned into a magnitude when we simplified the dot product. Therefore, to find the direction of the field you must use the [[184_notes:rhr|right-hand rule]] after (or before) you calculate the magnitude using Ampere's Law. When you do this, you will find that the magnetic field still curls around the current wire in the same way.+The final step here is to ask what is the direction of this B-field? With Ampere's Law, our magnetic field vector turned into a magnitude when we simplified the dot product. Therefore, to find the direction of the field you must use the [[184_notes:rhr|right-hand rule]] after (or before) you calculate the magnitude using Ampere's Law. When you do this, you will find that the magnetic field still curls around the current wire in the same way.
  
 ==== Ampere's Law Steps ==== ==== Ampere's Law Steps ====
 There are a few cases (besides outside a long wire) where Ampere's law is useful, including inside wires (as we mentioned before), [[https://en.wikipedia.org/wiki/Solenoid|solenoids]], and [[https://en.wikipedia.org/wiki/Toroid|toroids]]. In these other cases, the details may be different, but the steps that you would take would still be the same. These would include: There are a few cases (besides outside a long wire) where Ampere's law is useful, including inside wires (as we mentioned before), [[https://en.wikipedia.org/wiki/Solenoid|solenoids]], and [[https://en.wikipedia.org/wiki/Toroid|toroids]]. In these other cases, the details may be different, but the steps that you would take would still be the same. These would include:
-  - Figure out the general shape of the magnetic field. +  - Figure out and draw the general shape of the magnetic field. 
-  - Choose an Amperian loop that a) follows the magnetic field (to simplify the dot product) and that b) has a constant magnetic field along the length of the loop (to pull the B out of the integral). This lets you simplify the left side of the integral.+  - Choose an Amperian loop that a) goes through your observation point, b) follows the magnetic field (to simplify the dot product) and c) has a constant magnetic field along the length of the loop (to pull the B out of the integral). This lets you simplify the left side of the integral.
   - Find the current enclosed by the loop (maybe using current density if you need a fraction of the total current).   - Find the current enclosed by the loop (maybe using current density if you need a fraction of the total current).
-  - Solve for the magnitude of the magnetic field and double check the direction using the right hand rule. +  - Solve for the magnitude of the magnetic field 
 +  - Double check the direction of the magnetic field using the right hand rule. 
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